How Does the Split Option Work?

Pre-Conditions for using the 'Split' option:

• The number of players remaining in the game at the end of a deal is 3 or 2 on a table where the game started with more than 3 players.
• The number of players remaining in the game at the end of a deal is 2 on a table where the game started with 3 players.
• The number of drops/buy-in remaining after equating all players drops should be equal to at least 1 Entry fee.

A player has to request for prize and all remaining players have to accept split. Only then system will process the split request.

Among the players who accept for prize split, the split will be processed as follows:

1. Drops remaining for each of the players will be equated to that of the player with least drops remaining. After equating, the excess drops remaining with each player will be paidout from the prize pool as (number of excess drops remaining * Entry Fee)

2. The remaining amount in the prize pool will then be equally distributed among the players

For example: In a pool 101 table with r  25(0% service fee for simplicity sake) where the game started with more than 3 players and the table is now down to 3 players. Assuming Player1 has 3 drops remaining, Player2 has 1 drop and Player3 has no drops remaining respectively. Below representation is applicable even if there are rejoins on the table:

Prize Pool =r  150
1 drop =r  25
Player1: 3 Drops
Player2: 1 Drop
Player3: 0 Drops

System should first equate the number of drops remaining for each player to the player with least drops i.e. Player1 and Player2 will get a better cut of the prize pool

Player1: 3 X 25 =75, remaining drops: 0
Player2: 1 X 25 =25, remaining drops: 0
Player3: remaining drops: 0

Remaining Prize Pool =150 - 75 + 25 = r  50 (is greater than r  25 or 1 drop)
Remaining Prize Pool distribution =50/number of players remaining = 50/3 = ~ r  16.67

Prize split amounts:
Player1: 75+16.66 =91.66
Player2: 25+16.67 =41.67
Player3: 16.67